F flakine Junior Member Joined Aug 24, 2005 Messages 78 Jun 7, 2006 #1 ∫ x sec^2 x dx udv=uv-∫vdu u=x, du=dx, dv=sec^2 x dx, v=tan x x sec^2 x dx= xtan x-∫tan x dx= xtan x-ln|secx|+C Is this correct?
∫ x sec^2 x dx udv=uv-∫vdu u=x, du=dx, dv=sec^2 x dx, v=tan x x sec^2 x dx= xtan x-∫tan x dx= xtan x-ln|secx|+C Is this correct?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Jun 7, 2006 #2 Re: Intergration by Parts take the derivative of your solution to confirm the result ... it's a good habit to get into.
Re: Intergration by Parts take the derivative of your solution to confirm the result ... it's a good habit to get into.
F flakine Junior Member Joined Aug 24, 2005 Messages 78 Jun 7, 2006 #3 It looks good to me. The text has a different answer. xtan x + ln|cos x| =C
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Jun 7, 2006 #4 Same thing. Your answer is OK.
