H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 16, 2007 #1 Can someone help me ? Solve PV/T = P^v/t for P I tried doing it this way. V/t (P^v/T = V/t (P^v/t) PvV/tT=P Is this the right set-up?
Can someone help me ? Solve PV/T = P^v/t for P I tried doing it this way. V/t (P^v/T = V/t (P^v/t) PvV/tT=P Is this the right set-up?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Nov 16, 2007 #2 I can't tell what you have written. Is "PV" a single variable or is it "P*V". Maybe \(\displaystyle \L\frac{PV}{T}\;=\;\frac{P^{v}}{t}\) If so, ... \(\displaystyle \L\frac{PV}{T}*t\;=\;P^{v}\) \(\displaystyle \L\left(\frac{PV}{T}*t\\right)^{\frac{1}{v}}\;=\;P\)
I can't tell what you have written. Is "PV" a single variable or is it "P*V". Maybe \(\displaystyle \L\frac{PV}{T}\;=\;\frac{P^{v}}{t}\) If so, ... \(\displaystyle \L\frac{PV}{T}*t\;=\;P^{v}\) \(\displaystyle \L\left(\frac{PV}{T}*t\\right)^{\frac{1}{v}}\;=\;P\)
H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 16, 2007 #3 Intermediate Algebra tkhunny, Is the answer P = P^v/tTV correct? I will work on this a little more. Thank you for your help. Helen
Intermediate Algebra tkhunny, Is the answer P = P^v/tTV correct? I will work on this a little more. Thank you for your help. Helen
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Nov 16, 2007 #4 Solve PV/T = P^v/t for P Click to expand... is this ... \(\displaystyle \L \frac{PV}{T} = P^{\frac{v}{t}}\) or ... \(\displaystyle \L \frac{PV}{T} = \frac{P^v}{t}\) or something else?
Solve PV/T = P^v/t for P Click to expand... is this ... \(\displaystyle \L \frac{PV}{T} = P^{\frac{v}{t}}\) or ... \(\displaystyle \L \frac{PV}{T} = \frac{P^v}{t}\) or something else?
H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 16, 2007 #5 Intermediate Algebra skeeter, your second one is correct. Helen
O o_O Full Member Joined Oct 20, 2007 Messages 393 Nov 16, 2007 #6 Mmm I'm not sure how you went from: \(\displaystyle \L \frac{PV}{T} = \frac{P^{v}}{t}\) to \(\displaystyle \L \frac{V}{t} \cdot \frac{P^{v}}{T} = \frac{V}{t} \cdot \frac{P^{v}}{t}\) Anyway, try isolating P on one side of the equation: \(\displaystyle \L \frac{PV}{T} = \frac{P^{v}}{t}\) (Divide both sides by P and multiply both sides by t) \(\displaystyle \L \frac{Vt}{T} = \frac{P^{v}}{P^{1}}\) Now use your exponent rules to express the fraction on the right into one power. Then you can do what tkhunny did to get rid of the exponent. We're trying to solve just for P right?
Mmm I'm not sure how you went from: \(\displaystyle \L \frac{PV}{T} = \frac{P^{v}}{t}\) to \(\displaystyle \L \frac{V}{t} \cdot \frac{P^{v}}{T} = \frac{V}{t} \cdot \frac{P^{v}}{t}\) Anyway, try isolating P on one side of the equation: \(\displaystyle \L \frac{PV}{T} = \frac{P^{v}}{t}\) (Divide both sides by P and multiply both sides by t) \(\displaystyle \L \frac{Vt}{T} = \frac{P^{v}}{P^{1}}\) Now use your exponent rules to express the fraction on the right into one power. Then you can do what tkhunny did to get rid of the exponent. We're trying to solve just for P right?
H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 16, 2007 #7 Intermediate Algebra tkhunny, skeeter, o_0, Thank you all for the help you so generously give. Appreciated! Helen
Intermediate Algebra tkhunny, skeeter, o_0, Thank you all for the help you so generously give. Appreciated! Helen