I need help finding the inverse of h(x) = log5 (x+2).
M mallorymal New member Joined Feb 9, 2008 Messages 27 Feb 28, 2008 #1 I need help finding the inverse of h(x) = log5 (x+2).
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Feb 28, 2008 #2 Re: Inverse of this problem I am assuming that is base 5?. y=log5(x+2)\displaystyle y=log_{5}(x+2)y=log5(x+2) Remember the log law: logab=x\displaystyle log_{a}b=xlogab=x, then b=ax\displaystyle b=a^{x}b=ax
Re: Inverse of this problem I am assuming that is base 5?. y=log5(x+2)\displaystyle y=log_{5}(x+2)y=log5(x+2) Remember the log law: logab=x\displaystyle log_{a}b=xlogab=x, then b=ax\displaystyle b=a^{x}b=ax
