The inverse of the function \(\displaystyle f:[\frac{\pi}{2},\frac{3\pi}{2}]\rightarrow [-1,1], f(x)=\sin(x)\), is the function \(\displaystyle f^{-1}:[-1,1]\rightarrow [\frac{\pi}{2},\frac{3\pi}{2}]\) which is defined: ( right answer: pi-arcsinx)
pi+arcsinx
pi-arcsinx
arcsinx
2pi-arcsinx
-pi+arcsinx
I know the inverse of sin is arcsin but why is pi-arcsin ?
pi+arcsinx
pi-arcsinx
arcsinx
2pi-arcsinx
-pi+arcsinx
I know the inverse of sin is arcsin but why is pi-arcsin ?