rachelmaddie
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Can someone please check my work #15?
To find the inverse of h(x) = (2x + 6)/5, exchange x and y, then solve for y.
h(x) = (2x + 6) /5
y = 2x + 6/5 change to y —> x = (2y + 6)/5
To solve for y, first multiple each side by 5
5x = (2y + 6)/5*5
5x = 2y + 6
Subtract 6 from each side
5x - 6 = 2y + 6-6
5x - 6 = 2y
Divide by 2
(5x - 6)/2 = 2y/2
Therefore, The inverse is (5x - 6)/2
To find the inverse of h(x) = (2x + 6)/5, exchange x and y, then solve for y.
h(x) = (2x + 6) /5
y = 2x + 6/5 change to y —> x = (2y + 6)/5
To solve for y, first multiple each side by 5
5x = (2y + 6)/5*5
5x = 2y + 6
Subtract 6 from each side
5x - 6 = 2y + 6-6
5x - 6 = 2y
Divide by 2
(5x - 6)/2 = 2y/2
Therefore, The inverse is (5x - 6)/2
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