#### Dhamnekar Winod

##### Junior Member

- Joined
- Aug 14, 2018

- Messages
- 64

Hi,

How to integrate \(\displaystyle\int_0^\infty \tanh{(\pi*x)}*\left(\frac1x-\frac{x}{\frac{1}{16}+x^2}\right)dx\) and then how to express it in this format \(\frac{\pi^a}{b}-\ln{(c)}\), where

My attempt: We can rewrite this integral as \(\displaystyle\int_0^\infty \frac{\tanh{(\pi*x)}}{16*x^3+x}dx\). Now, how to proceed further?

My offline integral calculator gives me this answer

If any member knows the correct answer to this question, may reply to this question with correct answer.

How to integrate \(\displaystyle\int_0^\infty \tanh{(\pi*x)}*\left(\frac1x-\frac{x}{\frac{1}{16}+x^2}\right)dx\) and then how to express it in this format \(\frac{\pi^a}{b}-\ln{(c)}\), where

**a, b, c**are positive integers.My attempt: We can rewrite this integral as \(\displaystyle\int_0^\infty \frac{\tanh{(\pi*x)}}{16*x^3+x}dx\). Now, how to proceed further?

My offline integral calculator gives me this answer

**0.877263492537.**I don't understand how is that computed?If any member knows the correct answer to this question, may reply to this question with correct answer.

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