Win_odd Dhamnekar
Junior Member
- Joined
- Aug 14, 2018
- Messages
- 207
Hi,
How to integrate \(\displaystyle\int_0^\infty \tanh{(\pi*x)}*\left(\frac1x-\frac{x}{\frac{1}{16}+x^2}\right)dx\) and then how to express it in this format \(\frac{\pi^a}{b}-\ln{(c)}\), where a, b, c are positive integers.
My attempt: We can rewrite this integral as \(\displaystyle\int_0^\infty \frac{\tanh{(\pi*x)}}{16*x^3+x}dx\). Now, how to proceed further??
My offline integral calculator gives me this answer 0.877263492537. I don't understand how is that computed?
If any member knows the correct answer to this question, may reply to this question with correct answer.
How to integrate \(\displaystyle\int_0^\infty \tanh{(\pi*x)}*\left(\frac1x-\frac{x}{\frac{1}{16}+x^2}\right)dx\) and then how to express it in this format \(\frac{\pi^a}{b}-\ln{(c)}\), where a, b, c are positive integers.
My attempt: We can rewrite this integral as \(\displaystyle\int_0^\infty \frac{\tanh{(\pi*x)}}{16*x^3+x}dx\). Now, how to proceed further??
My offline integral calculator gives me this answer 0.877263492537. I don't understand how is that computed?
If any member knows the correct answer to this question, may reply to this question with correct answer.
Last edited: