By what reasoning did you arrive at your answer? You noted first that there are eight numbers on the spinner board. You listed out the numbers that are less than 4, but are not even (assuming the "or" here is the "exclusive or", or XOR, meaning "one of these conditions, but not both"). You listed out the numbers that are even, but are not less than 4. From ONE of the lists, you crossed out any duplicates, so you're not counting anything twice. You counted the remaining numbers and... got what?
I tried to answer it and got 3/4 or 6/8 after using the union set operation for 4/8 or 1/2 and 3/8, based on what is being asked in the problem.
What do you mean? I arrived at my answer on the basis that the statement is pertaining to the "or" that implies the union set operation, which is supported by this website: https://www.mathplanet.com/education/pre-algebra/probability-and-statistic/probability-of-events.By what reasoning did you arrive at your answer? You noted first that there are eight numbers on the spinner board. You listed out the numbers that are less than 4, but are not even (assuming the "or" here is the "exclusive or", or XOR, meaning "one of these conditions, but not both"). You listed out the numbers that are even, but are not less than 4. From ONE of the lists, you crossed out any duplicates, so you're not counting anything twice. You counted the remaining numbers and... got what?
What do I mean by... what?What do you mean?
Okay. But, as you noted, your answer is not among the answer-options listed. If one uses the exclusive, rather than the inclusive, "or", then one can arrive at one of the answer options.I arrived at my answer on the basis that the statement is pertaining to the "or" that implies the union set operation, which is supported by this website: https://www.mathplanet.com/education/pre-algebra/probability-and-statistic/probability-of-events.
How many of these eight numbers are even OR less than 4.
I tried to answer it and got 3/4 or 6/8 after using the union set operation for 4/8 or 1/2 and 3/8, based on what is being asked in the problem.
How many of these eight numbers are even OR less than 4.
Is 1 even or less than 4?
Is 2 even or less than 4?
Is 3 even or less than 4?
Is 4 even or less than 4?
Is 5 even or less than 4?
Is 6 even or less than 4?
Is 7 even or less than 4?
Is 8 even or less than 4?
Count the number of times you said yes and divide that number by 8. Reduce if necessary. Done
So, it's still 6/8 or 3/4 since reduction isn't necessary.How many of these eight numbers are even OR less than 4.
Is 1 even or less than 4?
Is 2 even or less than 4?
Is 3 even or less than 4?
Is 4 even or less than 4?
Is 5 even or less than 4?
Is 6 even or less than 4?
Is 7 even or less than 4?
Is 8 even or less than 4?
Count the number of times you said yes and divide that number by 8. Reduce if necessary. Done
MIIF listed four distinct answers so I was not sure that the OP was completely confident in their original answer. Yes, I saw that the answer was not listed.MIIF did just that, and got the correct answer. The issue is that 3/4 is not one of the choices. So the problem itself is bad.
You can also do it this way:
P(even OR <4) = P(even) + P(<4) - P(even AND <4) = 4/8 + 3/8 - 1/8 = 6/8 = 3/4
What did you mean regarding the answer that uses the exclusive "or"? I just came across this problem while reading the softcopy of a learning material, which does not directly contain a connection with the exclusive "or" and inclusive "or." ("Not directly" because, based from what I've read online, the inclusive "or" may correspond to the use of the union set operation, which is present in the material, and the exclusive "or" really has no tie to the material)What do I mean by... what?
As I have said before, the exclusive "or" is nowhere to be found in the material, and this is actually the first time I've encountered it, along with the inclusive "or, " which is, based from my research, really just the union set operation in this case. Here is what I mean:Okay. But, as you noted, your answer is not among the answer-options listed. If one uses the exclusive, rather than the inclusive, "or", then one can arrive at one of the answer options.
So either the exercise answer-options are wrong, or the use of the inclusive "or" is wrong. Consult your instructor for specifics.
MIIF listed four distinct answers so I was not sure that the OP was completely confident in their original answer. Yes, I saw that the answer was not listed.
I tried to answer [this problem.] [My answer was] 3/4 [(=6/8)]. [My strategy was to] us[e] the union set operation [on] 4/8 [(=1/2)] and 3/8 [i.e. \(\displaystyle \dfrac{4}{8} \bigcup \dfrac{3}{8}\)], based on what is being asked in the problem.
I interpreted it as you have (when I answered the same question at another site) and cannot deny that it was not well worded. But I cut kids a bunch of slack when their questions involve incorrect answer keys or incorrect multiple choices: they have a right to be confused under those circumstances.Actually, I think there's only one answer in their post, although it was written quite poorly, and, frankly, it was kind of a mess. Here's what I interpreted it as saying:
I guess you are correct.But I cut kids a bunch of slack when their questions involve incorrect answer keys or incorrect multiple choices: they have a right to be confused under those circumstances.
loli guess you are correct.