Is this correct? please lmk

Anifex

New member
Joined
Aug 17, 2019
Messages
12
I dont know how to type a fraction but the problem is
a/k=v/w
i got no solution but i think thats wrong
 
What are you instructed to do with this equation?
 
Solve each equation for the indicated variable.
a/k=v/w, for a.
I don't know how to type it in fraction form sorry
 
You've typed the fractions just fine; nothing more is needed.

To solve for a, you need to get the a by itself. That means you don't want the division by k.

What can you do to both sides, that will "undo" that division?
 
Solve each equation for the indicated variable.
a/k=v/w, for a.
I don't know how to type it in fraction form sorry
Good enough. Let's try something easier. Can you solve this for a: a+k=v
 
You've typed the fractions just fine; nothing more is needed.

To solve for a, you need to get the a by itself. That means you don't want the division by k.

What can you do to both sides, that will "undo" that division?
divide by A?
 
Solve each equation for the indicated variable.
a/k=v/w, for a.
I don't know how to type it in fraction form sorry
All this is asking is for you to say

[MATH]a = \text {some expession that is valid given what you know.}[/MATH]
To put it a different way, they are asking to isolate a on the LHS of the equation. That is what these "solve blah blah in terms of a" actually mean.

So to isolate a so it is the omly term on the LHS given

[MATH]\dfrac{a}{k} = \dfrac{v}{w}[/MATH],

you need to do what?
 
No, you want to leave a there; dividing by a would not get rid of the k.

What is the opposite of dividing by k?
 
multiplying by k?
Yes.

You need to end up with a alone on one side of the equation, to "isolate" a. That is what "solving in terms of a" means.

You have a very simple equation here where a is the numerator of a fraction. So you need to get rid of the denominator in a valid way. The only valid way to get rid of that denominator is to multiply both sides of the equation by the denominator (often called "clearing fractions.")

[MATH]\dfrac{a}{k} = \dfrac{v}{w} \implies k * \left ( \dfrac{a}{k} \right ) = k * \left ( \dfrac{v}{w} \right ) \implies a = \dfrac{kv}{w}.[/MATH]
You have isolated a in this case so you are done.
 
Top