Treeclimber
New member
- Joined
- Apr 18, 2009
- Messages
- 6
The 2 base angles of the isosceles triangle are 3y+4 and 7x+5. The other angle is x+8y=1. How do I find the measure of each angle?
Use what you know about the angle sum of any triangle, along with what you know about the relative sizes of the two base angles of any isosceles triangle. This knowledge allows you to create two equations (assuming the one "equals" sign is a typo for a "plus" sign):Treeclimber said:The 2 base angles of the isosceles triangle are 3y+4 and 7x+5. The other angle is x+8y=1.
Treeclimber said:… The other angle is x+8y=1 …
Treeclimber said:… i misstyped the problem here it what it really looks like …
…the other angle- x+8y= … <<< This is still not a valid expression for an angle, and there is no need to type a minus sign after the word "angle".
From your subsequent statements, it appears that you're trying to type: x + 8y - 1.
Please pay more attention to what you post; use the preview button to proofread your posts before submitting them.
… i used the addition method … <<< This is not worded properly. You're using the "elimination" method.
… 56x+77y=1376 … <<< You made an arithmetic mistake. 7 times 172 is not 1376.