D davemath New member Joined Jul 18, 2008 Messages 9 Jul 18, 2008 #1 It must be quite easy but I don't know why I cannot solve this: x*dy/dx = x^2 + y^2 + y Thank you for your helps in advance.
It must be quite easy but I don't know why I cannot solve this: x*dy/dx = x^2 + y^2 + y Thank you for your helps in advance.
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Jul 18, 2008 #2 Subtract \(\displaystyle y\) from both sides and divide by \(\displaystyle x^2\).
D davemath New member Joined Jul 18, 2008 Messages 9 Jul 18, 2008 #3 Hi, After that, at least I need one more step!! What I guess is d(y/x) = dy/x=y/x^2*dx
D davemath New member Joined Jul 18, 2008 Messages 9 Jul 18, 2008 #4 Hi, I think I know now..... Thanks a lot for your help!
D davemath New member Joined Jul 18, 2008 Messages 9 Jul 18, 2008 #5 No....I can still not solve the problem, can you help?
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Jul 19, 2008 #6 \(\displaystyle (y/x)' = 1 + (y/x)^2\).
D davemath New member Joined Jul 18, 2008 Messages 9 Jul 19, 2008 #7 Yes, I have also reached du/dx=1+u^2, but it looks not like Bernoulli equation......
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Jul 19, 2008 #8 \(\displaystyle du/(1+u^2) = dx\).
D davemath New member Joined Jul 18, 2008 Messages 9 Jul 19, 2008 #9 Hahaha, you must believe that I am stupid! Thanks a lot for your help.