# Jellybean question

#### intrakate1

##### New member
If i have a jar with 15 red, 13 yellow, and 7 green jelly beans what is the probability that i will pull out 1 red and 2 yellows (without the replacement of the ones i removed)

#### soroban

##### Elite Member
Hello, intrakate1!

If i have a jar with 15 red, 13 yellow, and 7 green jelly beans,
what is the probability that i will pull out 1 red and 2 yellows
(without the replacement of the ones i removed)?

$$\displaystyle \text{If you mean Red-\!Yellow-\!Yellow }in\;that\;order\text{, the probability is: } \;\frac{15}{35}\cdot\frac{13}{34}\cdot\frac{12}{33} \;=\;\frac{78}{1309}$$

$$\displaystyle \text{If you mean 1 red, 2 yellows }in\;any\;order\text{, the probability is: }\; \dfrac{{15\choose1}{13\choose2}}{{35\choose3}} \;=\;\frac{1170}{6545} \;=\;\frac{234}{1309}$$