Joint Probability Distribution

[Vickon]

Hello, I've been very sick this week and my prof has not returned my emails regarding missed notes. Please help me with this problem on expected value in joint probability distribution.

	x=4	x=10
y=1	0.3	0.2
y=2	0.1	0.4

What is E(X|y=2)?

I've tried to solve it as: E(X|y=2) = 4(0.1)+10(0.4) = 4.4
but I don't think this is correct. Any help would be greatly appreciated.

 

[Romsek]

it is correct

 

[Steven G]

E(X|y=2) = 4P(X=4|y=2) + 10P(X=10|y=2).
Using this formula you get the results you got. Good job.