paradoxed21
New member
- Joined
- Mar 28, 2013
- Messages
- 13
Please help, whats the answer if you take E=MC squared and mulitply it by any number less than 1? (E=mc2)*0.05
Last edited:
Please help, whats the answer if you take E=MC squared and mulitply it by any number less than 1?
(E=mc2)*0.05 | |
As posted, this question does not make sense - at least to me.
Please post the EXACT problem - verbatim.
What's the answer if you take E=mc2and mulitply it by any number less than 1?
(E=mc2)*0.05
You sure you didn't post that after consuming a 40ouncer of Canadian Club, Paradoxed?
(speed = distance / time) * 1/2 ; what's the answer to this similar one?
paradoxed21,
I still don't think you posted a correct complete exercise.
So replacing m by (1/2)m changes the energy to \(\displaystyle E= ((1/2)m)c^2= (1/2)mc^2\). Replacing m by (1/3)m changes the energy to \(\displaystyle E= ((1/3)m)c^2= (1/3)mc^2\). Do you see the point?
E = mc^2 is a part of a bigger picture, in which space-time is four dimensional. The actual dimensions aresoroban's second example indicates with the use of the above equation you can link the Theory of Relativity to the Pythagorean Theorem which in a sense is a basis for quantum Physics. I.E. A squared + B squared = C squared! Thus being relative to B squared - A squared= C squared which I believe is the equation of Proper Time being In terms of four-dimensional space-time, proper time is analogous to arc length in three-dimensional (Euclideann) space. My hypotheses = Light Speed = 0! This would open a multitude of possibilities. Thank you Soroban, although with a hint of sarcasm you indeed assisted. If anyone can find I hole in my deduction please feel free to point out.
I now have to ponder whether you really don't know how to do arithmetic or this whole thread is a joke. Just in case you are serious, no, going from "E" to "(1/2)E" is NOT increasing E. Technically, we would say that, in "\(\displaystyle E= mc^2\)", "E is proportional to m". Whatever m is multiplied by, 1/2 or 1/3 or 2, E is also multiplied by.Energy increases, right?
I now have to ponder whether you really don't know how to do arithmetic or this whole thread is a joke. Just in case you are serious, no, going from "E" to "(1/2)E" is NOT increasing E. Technically, we would say that, in "\(\displaystyle E= mc^2\)", "E is proportional to m". Whatever m is multiplied by, 1/2 or 1/3 or 2, E is also multiplied by.
Dr. Phil, I don't see this as really a question about "relativity", just a question about "proportionality".
I now have to ponder whether you really don't know how to do arithmetic or this whole thread is a joke. Just in case you are serious, no, going from "E" to "(1/2)E" is NOT increasing E. Technically, we would say that, in "\(\displaystyle E= mc^2\)", "E is proportional to m". Whatever m is multiplied by, 1/2 or 1/3 or 2, E is also multiplied by.
Dr. Phil, I don't see this as really a question about "relativity", just a question about "proportionality".
The equaton \(\displaystyle E = mc^2\) is not a mathematical abstraction, but rather a description of the physical universe. As with all physical quantities, each symbol represents specific units.To answer your question yes, serious question and the arithmetic is very rusty. I will explain in full:
There is an equation that when E of E=mc2 is less than 1 but more than 0 and M=2 when inverting (again Im going by what ive heard.) would show 1/2/2 =2/1C2 to get the equation taking a particle less than 1 and inducing an increase in energy! Which has been thrown out due to Thermodynamic Laws of Conservation of energy as a glitch or an infinite... 1/2=E 1/2=M so 1/2=1/2C2 would show (I think)when multiplied you get an increase right? my apologies for my processing time Soto speak.
Yes, \(\displaystyle E/m = c^2\) expresses the fact that energy is proportional to mass. More mass is equivalent to more energy. If you start with twice as much mass and convert it to energy, you will get twice as much energy. Doesn't that make sense?E=MC2 converted to E/M=C2 is the equation that will confirm an increase in Energy...
The equaton \(\displaystyle E = mc^2\) is not a mathematical abstraction, but rather a description of the physical universe. As with all physical quantities, each symbol represents specific units.
E = Energy in (kg·m/s^2), a unit also known as a Joule
m = mass in (kg)
c = velocity of light in (m/s) = 299,792,458 m/s (exact)
The equation is true for any mass: if you double the mass you double the energy. The constant of proportionality, c^2, is taken to be a universal constant. Are you proposing studying an alternate universe with a different value of c^2 ?
Your statement E = 1/2 in nonsense unless you write the units: a correct statement would be E = 1/2 J.
Likewise m = 1/2 means nothing unless you include units: m = 1/2 kg.
Then substituting those values in the equation, (1/2 J) = (1/2 kg)×c^2 is true.
Yes, \(\displaystyle E/m = c^2\) expresses the fact that energy is proportional to mass. More mass is equivalent to more energy. If you start with twice as much mass and convert it to energy, you will get twice as much energy. Doesn't that make sense?
2 kg of sugar has twice the calories of 1 kg of sugar.
2 cu.ft. of natural gas gives you twice the heat of 1 cu.ft.