laplace transform of 2 A e^-2at[u(t)-U(t-3T)

[khan555]

Hi, I'm finding it a real struggle to figure out the Laplace Transform of 2 A e^-2at[u(t)-U(t-3T), I think the two delays are causing the confusion

("a" being alpha)
I would appreciate if anyone could help me find the solution

Thank you

 

[Deleted member 4993]

Hi, I'm finding it a real struggle to figure out the Laplace Transform of 2 A e^-2at[u(t)-U(t-3T), I think the two delays are causing the confusion

("a" being alpha)
I would appreciate if anyone could help me find the solution

Thank you

Several problem with the post:

i)..... Incomplete bracket []

ii).....Is there a difference between 'u' and 'U' - if yes what is it?

ii).....Is there a difference between 't' and 'T' - if yes what is it?

 

[Ishuda]

Hi, I'm finding it a real struggle to figure out the Laplace Transform of 2 A e^-2at[u(t)-U(t-3T), I think the two delays are causing the confusion

("a" being alpha)
I would appreciate if anyone could help me find the solution

Thank you

I would add to the questions Subhotosh Khan has. For example is this supposed to be
\(\displaystyle 2\, A\, exp^{-2\, \alpha\, t}\, [\, u(t)\, - u(t-3T)\, ]\)
or
\(\displaystyle 2\, A\, exp^{-2\, \alpha\, t\, [\, u(t)\, - u(t-3T)\, ]}\)
or ...

I would also think that the u(t) is the Heaviside step function. You might look at
https://en.wikipedia.org/wiki/Laplace_transform