B bing.thio New member Joined Mar 20, 2020 Messages 1 Mar 20, 2020 #1 My question is regarding number 24! How can you manipulate the (1-sin^2(t)) term into a (1-cos(2t)/2 term?
My question is regarding number 24! How can you manipulate the (1-sin^2(t)) term into a (1-cos(2t)/2 term?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,325 Mar 20, 2020 #2 One for free. This is why we study trigonometry before we study differential equations. cos(2t) = 1 - 2sin2(t) sin2(t) = [1 - cos(2t)]/2 ..........................edited Better brush up. It doesn't get easier.
One for free. This is why we study trigonometry before we study differential equations. cos(2t) = 1 - 2sin2(t) sin2(t) = [1 - cos(2t)]/2 ..........................edited Better brush up. It doesn't get easier.
D Deleted member 4993 Guest Mar 20, 2020 #3 bing.thio said: View attachment 17304 My question is regarding number 24! How can you manipulate the (1-sin^2(t)) term into a (1-cos(2t)/2 term? Click to expand... use cos(2t) = cos2(t) - sin2(t)
bing.thio said: View attachment 17304 My question is regarding number 24! How can you manipulate the (1-sin^2(t)) term into a (1-cos(2t)/2 term? Click to expand... use cos(2t) = cos2(t) - sin2(t)
