#### The Preacher

##### Junior Member

- Joined
- Sep 13, 2005

- Messages
- 53

A parallelogram with sides of 6 and 10 has an area of \(\displaystyle \

30\sqrt 2

\\). Find the measure of each angle of the parallelogram.

Small angle _____\(\displaystyle \

^\circ

\\)

Large angle _____\(\displaystyle \

^\circ

\\)

Just about all I can think of is that the opposite angles will be equal (duh). If I can figure out one angle, then I can double it. Then I can take that sum and subtract it from 360 \(\displaystyle ^\circ\), and divide that difference by two to get my other angle.

Let x be the measure of angle 1, and y be the measure of angle 2.

360-\(\displaystyle \

x^2

\\)=\(\displaystyle y^2\)

If I can figure out x or y, I can figure out the other. Can anyone give me a hint in the right direction?

I hope the equation I just came up with isn't common knowledge or something I'm supposed to know already. Haha. Thanks a lot.

-The Preacher