LIM LN(-x)= -infinity
x->0-
so answer: -infinity*2 = -infinity
LIM LN(2-2x)
x->1-
How would you guys begin to solve this limit?
without a calculator or graphing utility?
do you have to plugin numbers in your head?
or is there some easier process?
thanks
do I just have to memorize the graph
Hi Mark,
No, we don't need to memorize the graph of y = ln(2-2x)
We need to memorize the graph of y = ln(x)
After that, it helps to understand the topic of graph transformations (from precalculus); that is, if you know the steps to go from the graph of ln(x) to the graph of ln(2-2x), then you can "see" that the general behavior of ln(2-2x) as x approaches 1 from the left is the same as the behavior of ln(x) as x approaches zero from the right.
Cheers :cool:
so there is no way around memorizing graphs?