What? I am supposed to get 2015e^2014Why are you doing all this work? The limit equals f'(2021).
Okay, what do I do then?3rd line from the bottom is wrong. Let0, represent not 0--some number other than 0.
0/0= 0, that is a true 0/0= 0. However something approaching 0 divided by something approaching 0 is not necessarily 0
So you are not getting f'(2014) = 2015e^2014 or did you not try? I suspect that it is the latter, so just try and you'll see that you get the correct answer.What? I am supposed to get 2015e^2014
Recognize that the limit is simply f'(2014). That is what the author wanted you to do with this exercise.Okay, what do I do then?
I am having trouble understanding you. The limit's solution is supposed to be 2015e^2014, i tried to solve the problem and got e^2014.So you are not getting f'(2014) = 2015e^2014 or did you not try? I suspect that it is the latter, so just try and you'll see that you get the correct answer.
Rewrite your limit with one change--replace x with h. Then decide if you see that the limit equals f'(2014)
IRecognize that the limit is simply f'(2014). That is what the author wanted you to do with this exercise.
What does f' have to do here, please explain?So you are not getting f'(2014) = 2015e^2014 or did you not try? I suspect that it is the latter, so just try and you'll see that you get the correct answer.
Rewrite your limit with one change--replace x with h. Then decide if you see that the limit equals f'(2014)
How's that?The limit equals f'(2021).
Fine, the limit equals f'(2014). Are you happy now? Happy New Year!How's that?
To see that the limit is f'(2014) you need to do as I say. Please rewrite the limit using h instead of x. Post back that limit and we will go from there.I
What does f' have to do here, please explain?
The student need to recognize that this is a limit of the quotient function which is simply a derivative.Have you learned l'Hopital's rule?
YessHave you learned l'Hopital's rule?
I would like to realize that but I am not even sure I know what a quotient function is.The student need to recognize that this is a limit of the quotient function which is simply a derivative.
Jomo meant that you can compute the derivative of f(x) using the product rule and evaluate it in 2014. Why do you need to do it through the definition of the derivative?Why are you doing all this work? The limit equals f'(2014).
Jomo is saying here that it's not x->inf; you should use another variable to indicate the "steps" size, typically h.3rd line from the bottom is wrong. Let0, represent not 0--some number other than 0.
0/0= 0, that is a true 0/0= 0. However something approaching 0 divided by something approaching 0 is not necessarily 0
I meant to say the difference quotient. It is the quotient used in the definition of a derivative.I would like to realize that but I am not even sure I know what a quotient function is.