Limits: limit, as x -> 0, of 1 - cos2x / xsin2x

[Silvia]

Lim 1-cos2x/xsin2x
x->0

 

[pka]

Lim 1-cos2x/xsin2x
x->0

Is this a correct reading \(\displaystyle \displaystyle{\lim _{x \to 0}}\dfrac{{1 - \cos (2x)}}{{x\sin (2x)}}~?\)

If so, then you need to respond with showing your own work.

Or tell what is correct using grouping symbols.

 

[stapel]

Lim 1-cos2x/xsin2x
x->0

I have moved your posting from "Arithmetic" to the appropriate category. I have provided your post with a useful subject line. However, I cannot correct your formatting, as it currently admits of too many possible interpretations.

Kindly please reply using standard web-safe formatting (here), paying especially attention to grouping symbols. When you reply, please include a clear listing of your efforts so far, as you saw in the "Read Before Posting" thread that you read before posting (right?).