limits

You have \(\displaystyle \lim_{x\to 0}\frac{sec(2x)}{\sqrt{x}}+4\)?.

Do you mean \(\displaystyle \lim_{x\to 0}\frac{sec(2x)}{\sqrt{x}+4}\)?.

Maybe \(\displaystyle \lim_{x\to 0}\frac{sec(2x)}{\sqrt{x+4}}\)?.
 
The problem in the middle of your post. Sorry, i could figure out how to put it in the correct way.
 
In that event, rewrite as:

\(\displaystyle \lim_{x\to 0}\frac{1}{cos(2x)(\sqrt{x}+4)}\)

Now, just plug in x=0 and you can see the limit.

You really do not even have to do that. Just sub in x=0 as is.
 
so the answer is 1? i'm just having trouble figuring out which steps to take.
 
No, the answer is not 1.

There are no steps to take. This is one of those easy limits you can just sub into. Most are not like that.

If you sub x=0 into sec(2x), what do you get?.

If you sub x=0 into \(\displaystyle \sqrt{x}+4\), what do you get?.
 
If you sub x=0 into sec(2x), what do you get?. you get 1

If you sub x=0 into , what do you get?. you get 2

so the answer will be 1/2?
 
The top is correct. But \(\displaystyle \sqrt{0}+4\) does not equal 2.
 
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