R robbie New member Joined Jul 2, 2015 Messages 1 Jul 2, 2015 #1 The plane that passes through the point (−3,−5,2) and is perpendicular to both x+4z=0 and 5z−(4x+5y)=−7 has as its implicit equation. How would you solve this? This is Linear Algebra I think.
The plane that passes through the point (−3,−5,2) and is perpendicular to both x+4z=0 and 5z−(4x+5y)=−7 has as its implicit equation. How would you solve this? This is Linear Algebra I think.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jul 3, 2015 #2 robbie said: The plane that passes through the point (−3,−5,2) and is perpendicular to both x+4z=0 and 5z−(4x+5y)=−7 has as its implicit equation. Click to expand... Rewrite \(\displaystyle 5z-(4x+5y)=-7\) as \(\displaystyle 4x+5y-5z=7\). The norma is \(\displaystyle <1,0,4>\times <4,5,-5>\). See here,
robbie said: The plane that passes through the point (−3,−5,2) and is perpendicular to both x+4z=0 and 5z−(4x+5y)=−7 has as its implicit equation. Click to expand... Rewrite \(\displaystyle 5z-(4x+5y)=-7\) as \(\displaystyle 4x+5y-5z=7\). The norma is \(\displaystyle <1,0,4>\times <4,5,-5>\). See here,
