Linear Combinations (I think)

Imum Coeli

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Dec 3, 2012
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Hi I have a question and I'm afraid that i missed something.

Q: A retail grocery merchant figures that her daily gain from sales $X\displaystyle X is a normally distributed random variable with μ=50\displaystyle \mu =50 and σ=3\displaystyle \sigma = 3 . X\displaystyle X can be negative if she has to dispose of enough perishable goods. Also, she figures daily overhead costs are $Y\displaystyle Y , which have an Erlang distribution of order n=4\displaystyle n=4 and common rate λ=0.5\displaystyle \lambda = 0.5. if X\displaystyle X and Y\displaystyle Y are independent, find the expected value and variance of her daily net gain.

A:
Let P\displaystyle P be her daily net gain then

P=XY\displaystyle P = X - Y

So the expected valued of P\displaystyle P is

E[P]=E[X]E[Y]\displaystyle E[P] = E[X]-E[Y]

and since XN(50,3)    E[X]=50\displaystyle X \sim \text{N}(50,3) \implies E[X] = 50 and YErl(4,0.5)    E[Y]=40.5=8\displaystyle Y \sim \text{Erl}(4,0.5) \implies E[Y]= \frac{4}{0.5} = 8 then

E[P]=42\displaystyle E[P]= 42 (coincidentally her expected profit is the meaning of life).

Now the variance of P\displaystyle P is

var(P)=var(X)+var(Y)\displaystyle \text{var}(P) = var(X) + var(Y) since independent.

and XN(50,3)    var(X)=32=9\displaystyle X \sim \text{N}(50,3) \implies \text{var}(X)= 3^2=9 and YErl(4,0.5)    var(Y)=4(0.5)2=16\displaystyle Y \sim \text{Erl}(4,0.5) \implies \text{var}(Y)= \frac{4}{(0.5)^2} = 16 then

var(P)=25\displaystyle \text{var}(P) = 25 .


(Sorry if this seems like a stupid question but we have just had a baby two days ago and I need to talk about this problem. Hopefully I don't look too much like an idiot :D)
 
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