Imum Coeli
Junior Member
- Joined
- Dec 3, 2012
- Messages
- 86
Hi I have a question and I'm afraid that i missed something.
Q: A retail grocery merchant figures that her daily gain from sales $X is a normally distributed random variable with μ=50 and σ=3. X can be negative if she has to dispose of enough perishable goods. Also, she figures daily overhead costs are $Y, which have an Erlang distribution of order n=4 and common rate λ=0.5. if X and Y are independent, find the expected value and variance of her daily net gain.
A:
Let P be her daily net gain then
P=X−Y
So the expected valued of P is
E[P]=E[X]−E[Y]
and since X∼N(50,3)⟹E[X]=50 and Y∼Erl(4,0.5)⟹E[Y]=0.54=8 then
E[P]=42 (coincidentally her expected profit is the meaning of life).
Now the variance of P is
var(P)=var(X)+var(Y) since independent.
and X∼N(50,3)⟹var(X)=32=9 and Y∼Erl(4,0.5)⟹var(Y)=(0.5)24=16 then
var(P)=25.
(Sorry if this seems like a stupid question but we have just had a baby two days ago and I need to talk about this problem. Hopefully I don't look too much like an idiot
)
Q: A retail grocery merchant figures that her daily gain from sales $X is a normally distributed random variable with μ=50 and σ=3. X can be negative if she has to dispose of enough perishable goods. Also, she figures daily overhead costs are $Y, which have an Erlang distribution of order n=4 and common rate λ=0.5. if X and Y are independent, find the expected value and variance of her daily net gain.
A:
Let P be her daily net gain then
P=X−Y
So the expected valued of P is
E[P]=E[X]−E[Y]
and since X∼N(50,3)⟹E[X]=50 and Y∼Erl(4,0.5)⟹E[Y]=0.54=8 then
E[P]=42 (coincidentally her expected profit is the meaning of life).
Now the variance of P is
var(P)=var(X)+var(Y) since independent.
and X∼N(50,3)⟹var(X)=32=9 and Y∼Erl(4,0.5)⟹var(Y)=(0.5)24=16 then
var(P)=25.
(Sorry if this seems like a stupid question but we have just had a baby two days ago and I need to talk about this problem. Hopefully I don't look too much like an idiot
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