Linear eq. system solution?

thomasvt

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Sep 20, 2019
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I have a physical problem that I already turned into a system of equations:

q*t = c + x*t (1)
e*t = f + y*t (2)
x^2 + y^2 = g^2 (3)

I wanted to solve it, but the result gets complicated and I wonder if there is a simpler solution.
I basically solve for x from (3), use that in (1) to solve for y. Then I use that in (2) to solve for t:

(3) => x = sqrt(g^2 - y^2) (4)
use (4) in (1) => q*t = c + sqrt(g^2 - y^2)*t => t = c / (b-sqrt(g^2-y^2)) (5)
(2) => e = f/t + y (6)
use (5) in (6) => e = f/c * (b-sqrt(g^2-y^2)) + y

and then I let WolframAlpha solve for y (because I forgot how to do things like this myself :) ) which gives this:


Is this an OK solution? or is there a simpler method?

Thank you
 
I have a physical problem that I already turned into a system of equations:

q*t = c + x*t (1)
e*t = f + y*t (2)
x^2 + y^2 = g^2 (3)

I wanted to solve it, but the result gets complicated and I wonder if there is a simpler solution.
I basically solve for x from (3), use that in (1) to solve for y. Then I use that in (2) to solve for t:

(3) => x = sqrt(g^2 - y^2) (4)
use (4) in (1) => q*t = c + sqrt(g^2 - y^2)*t => t = c / (b-sqrt(g^2-y^2)) (5)
(2) => e = f/t + y (6)
use (5) in (6) => e = f/c * (b-sqrt(g^2-y^2)) + y

and then I let WolframAlpha solve for y (because I forgot how to do things like this myself :) ) which gives this:


Is this an OK solution? or is there a simpler method?

Thank you
You have three equations - what bare your unknowns (and "knowns").

Using WA is perfectly OK with us - as long as your instructor agrees with its usage.
 
oh, sorry about that: the unknowns are x, y and t, the rest are constants...

btw, I am 38 years old gamedeveloper. Most problems I can solve myself, but i'd like some backup on this one in case I make mistakes.

thanks in advance!
 
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