Linear Equation: (5/3x)-(5/2)=-(4/9)

crappiefisher26

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Jul 23, 2006
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Ok heres the question. (5/3x)-(5/2)=-(4/9)

Here is how i understand how to figure it out. It asks me to solve for x, write answer as fraction and in simpilest form.

6(5/3x-5/2)=6(-4/9)

then i got
6(5/3x)-6(-5/2)=6(-4)

30x-30=-24

30x-30+30=-24

30x=-24

Then i divided both sides by 30 and got -(4/5) but that wasnt right.

heres another question that i asked my professor about. same type.

(9/8x)+(3/4)=(7/2)

8((9/8x)+(3/4))=8(7/2)

8(9/8x)+8(3/4)=8(7/2)

9x+2(3)=4(7) simplifies to 9x+6=28

then he got 9x+6-6=28-6

9x=22, then he divided both sides by 9 and got (22/9).

Im really confused. cause i did a couple and emailed him all my work and answers and they were wrong. So i dont know what to do anymore.
 
Re: Linear Equation

crappiefisher26 said:
Ok heres the question. (5/3x)-(5/2)=-(4/9)

Here is how i understand how to figure it out. It asks me to solve for x, write answer as fraction and in simpilest form.

6(5/3x-5/2)=6(-4/9)

then i got
6(5/3x)-6(-5/2)=6(-4)

Your next step should read \(\displaystyle 10x +15 = -8/3\).
 
crappiefisher26 said:
(5/3x)-(5/2)=-(4/9)

6(5/3x-5/2)=6(-4/9)

6(5/3x)-6(-5/2)=6(-4)

30x-30=-24
What you posted would seem to indicate the following:

. . . . .\(\displaystyle \L \frac{5}{3x}\,-\,\frac{5}{2}\,=\,-\frac{4}{9}\)

But going from the third line (in the quote above) to the fourth seems to indicate that you meant the following:

. . . . .\(\displaystyle \L \frac{5}{3}\,x\,-\,\frac{5}{2}\,=\,-\frac{4}{9}\)

Is this latter guess correct? That is, did you mean "(5/3)x - 5/2 = -4/9"? Also, the only way the 6 could have multiplied (on the right-hand side) to give a "-4" would be if that fraction were a "-4/6" rather than "-4/9". Please confirm or correct.

Thank you.

Eliz.
 
this is correct. But im all confused now on how to do it from start to finish.
Could ya write it out and reply back to me.
Thanks.
 
Given: \(\displaystyle \L \;\frac{5}{3}\,x\,-\,\frac{5}{2}\,=\,-\frac{4}{9}\)

Add \(\displaystyle \L \,\frac{5}{2}\): \(\displaystyle \;\L \frac{5}{3}\,x\,=\,\frac{37}{18}\)

Divide by \(\displaystyle \L \,\frac{5}{3}\): \(\displaystyle \L \;x\,=\,\frac{37}{30\)
 
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