Remember that the quotient of two NEGATIVE numbers is positive. The numerator of your fraction is negative; if the denominator is also negative, the quotient will be greater than 0.
So, we want all values of x for which
3 - x < 0
is true.
Add x to both sides of the inequality:
3 < x
or, if you'd prefer,
x > 3
Now, let's check by picking a value of x which is greater than 3, say 5. Substitute 5 for x in the original inequality:
-2 / (3 - 5) > 0
-2 / (-2) > 0
1 > 0 <--------True
The solution for this inequality, then, is all x for which x > 3.
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