FrasierCrane
New member
- Joined
- Jun 18, 2015
- Messages
- 2
Hi folks, thanks for your time.
I have become stuck on what is probably a very simple question relating to linear systems.
I have three linear equations:
Solving by gauss-Jordan I have come to the conclusion that x = -2, y = 5, z = 3.
But now I have been asked to find all the values of a, for which this system is consistent, giving algebraic reasoning. I am very stuck here, I have tried gauss-Jordan again, this time replacing the -3 for unknown coefficient a. But with no success. If anyone could shed some light that would be most helpful, cheers
I have become stuck on what is probably a very simple question relating to linear systems.
I have three linear equations:
3x+y-2z=-7
-az=x+y+6
2x+2y+z=9
The coefficient for z in equation 2 is -3, therefore if my maths is correct we can rearrange equation 2 to become x+y-3z= -6.-az=x+y+6
2x+2y+z=9
Solving by gauss-Jordan I have come to the conclusion that x = -2, y = 5, z = 3.
But now I have been asked to find all the values of a, for which this system is consistent, giving algebraic reasoning. I am very stuck here, I have tried gauss-Jordan again, this time replacing the -3 for unknown coefficient a. But with no success. If anyone could shed some light that would be most helpful, cheers