Lines and planes
- Thread starter Gasim
- Start date
Cubist
Senior Member
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- Oct 29, 2019
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Question... Write down vector equation of a line which is an intersection of two planes:
x - y + 2z + 4 = 0
-2x + y + z + 3 = 0
@Gasim You'll need to find a point on the line and a direction vector (for the line). Please show an attempt, or explain more about where you're stuck...
x - y + 2z + 4 = 0
-2x + y + z + 3 = 0
@Gasim You'll need to find a point on the line and a direction vector (for the line). Please show an attempt, or explain more about where you're stuck...
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pka
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To write the equation of the line of intersection we need a point on both planes and a direction vector..
I suggest finding a point [imath] (0,y,z)[/imath] that is on both planes.
Then compute [imath] {D}=\left\langle {1, - 1,2} \right\rangle\times \left\langle {-2,1,1} \right\rangle[/imath] the direction vector.
I suggest finding a point [imath] (0,y,z)[/imath] that is on both planes.
Then compute [imath] {D}=\left\langle {1, - 1,2} \right\rangle\times \left\langle {-2,1,1} \right\rangle[/imath] the direction vector.