List of sas triangle problems

[neilo]

I have tried asking A.I. this question, but get bad results. I basically want a list of opposite sides to common angles using 2 known sides of 1 unit adjacent to a variable angle given in the list below
1,2,3,4,5,10,15,20,22.5,25,30,35,40,45,50,55,60,65,67.5,70,75,80,85,90,100,110,120,130,135,140,150,160,170,175,176,177,178,179,180

A.I. has been giving me some really unreliable answers. I wonder if anyone can help please?

 

[mmm4444bot]

List of sas triangle problems

Is this homework?

 

[neilo]

I want a layout reference sheet for easily assembling fabrications with a given angle. I can simply multiply the answers by whatever measurements I have. Or bisect the sides at a convenient unit multiple.and measure to those marks.

 

[neilo]

For example. I can position two 1metre lengths of steel touching at one end and 1.414 between the other ends to create a right angle. Or 1 meter apart for 60 degrees.

 

[Otis]

opposite side to common angles using 2 known sides of 1 unit adjacent to a [given] angle

Hi neilo. This image is from one of many sites that discuss sas cases.



Instead of side p=6.9 and q=2.6, your situation has both lengths equal 1. Substituting 1 for p and q, and one of your angles for R, simplifies the expression for r².

 

[Otis]

I want a layout reference sheet for easily assembling fabrications with a given angle.

Hi neilo. I didn't see your response above, when I'd replied earlier. Sounds like your need is not homework.

Google will provide the lengths of the third side, when the adjacent sides are 1-unit. Copy and paste the following expression, changing the degrees as needed.

sqrt(2-2*cos(60 degrees))

The result ought to be displayed at the top of the page, but if you use a smartphone then you might need to scroll past a couple Google suggestions to see it.

 

[neilo]

I've seen the formula before, but I have done like you suggested and now have a link on my notes app that takes me straight to the Google page where I can simply substitute the angle value in the expression. Easier than making a list or thinking too much. I'm glad I asked the question. Thanks very much