Logarithm problem - Solve for x - PLEASE HELP!

[moodeyes113]

Solve. Round to the thousandths.

(1/2 log of base x)^-2 = 4

:shock:

:!: I have no idea how to solve this! Please help! :!:

 

[tkhunny]

Solve. Round to the thousandths.

(1/2 log of base x)^-2 = 4

:shock:

:!: I have no idea how to solve this! Please help! :!:

Sadly, niether does anyone else, since the notation makes no sense at all.

Do you mean [½*log(x)]^(-2) = 4? That we can do. Can you?

 

[moodeyes113]

A little correction... plz help

Solve. Round to the thousandths.

(1/2 log of 3 base x)^-2 = 4

Shocked

:!: I have no idea how to solve this! Please help! :!: :shock:

 

[tkhunny]

Re: A little correction... plz help

(1/2 log of 3 base x)^-2 = 4

You need to know algebra and log rules.

(1/2 log of 3 base x)^-2 = 4
(1/2 log of 3 base x)^2 = 1/4
(1/2 log of 3 base x) = 1/2 or (1/2 log of 3 base x) = -1/2
log of 3 base x = 1 or log of 3 base x = -1
x = 3 or 1/x = 3
x = 3 or x = 1/3

Try them in the ORIGINAL equation and see if they work.

 

[stapel]

Solve....(1/2 log of base x)^-2 = 4

...the notation makes no sense at all.

Solve....(1/2 log of 3 base x)^-2 = 4

Did you read the reply you received?

Repeating non-sensical non-notation won't make your question any more understandable.

If you don't know the topic well enough to use the formatting advice (available in the "Forum Help" pull-down menu at the very top of the page) to put your question in some recognizable form, then there is little hope (1) of anybody else understanding the question either or (2) of you understanding any suggestion of how to find a solution.

Sorry.

Eliz.

 

[moodeyes113]

tkhunny,

Thank you very much for your help. I truly appreciate it.
&
HAPPY NEW YEAR!



Stapel,

Please do not be so harsh. You have no right to say anything unless you attempted to help out with this problem. Do not be so quick to judge and I hope that you put "being understanding" at the top of your New Year's resolutions. I hope that you have a HAPPY NEW YEAR!

 

[tkhunny]

Frankly, I have to agree with stapel. I just took a guess at what the notation meant. It could be right or wrong.

 

[stapel]

You have no right to say anything unless you attempted to help out with this problem.

Really? When were you put in charge of this forum? (And asking for clarification of what the question might actually be is "attempting to help out".)

Do not be so quick to judge

I read what you and the tutor posted, and asked you please to have the consideration to speak clearly. The only one being judgemental and condemnatory is you.

Sheesh. How much more of this "holiday spirit" can I stand?

Eliz.