L Levornia New member Joined May 12, 2010 Messages 1 May 12, 2010 #1 Log[base 5] 1/125 = x I am to solve. Honestly I don't know where to start...I know the formulas and I have studied but this just doesn't make since to me. Please help
Log[base 5] 1/125 = x I am to solve. Honestly I don't know where to start...I know the formulas and I have studied but this just doesn't make since to me. Please help
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 May 12, 2010 #2 \(\displaystyle log_5\bigg(\frac{1}{125}\bigg) \ = \ x\) \(\displaystyle log_5\bigg(\frac{1}{5^3}\bigg) \ = \ x\) \(\displaystyle log_5(5^{-3}) \ = \ x\) \(\displaystyle Ergo, \ 5^{-3} \ = \ 5^x, \ x \ = \ -3\)
\(\displaystyle log_5\bigg(\frac{1}{125}\bigg) \ = \ x\) \(\displaystyle log_5\bigg(\frac{1}{5^3}\bigg) \ = \ x\) \(\displaystyle log_5(5^{-3}) \ = \ x\) \(\displaystyle Ergo, \ 5^{-3} \ = \ 5^x, \ x \ = \ -3\)
