K kimbero5 New member Joined Sep 11, 2005 Messages 20 Sep 25, 2005 #1 9^(2x+1)=27???? take the log w/ base 9 of each side ad get 2x+1=logbase 9 27 and then what do i do???
9^(2x+1)=27???? take the log w/ base 9 of each side ad get 2x+1=logbase 9 27 and then what do i do???
G Guest Guest Sep 25, 2005 #2 2x+1=logbase 9 27 use change of base rule on the right hand side log base9 27 = log 27/log 9 both to base 10 = log (3)^3 / log (3)^2 = 3 log 3 / (2 log3) = 3/2 and the solve. all the best
2x+1=logbase 9 27 use change of base rule on the right hand side log base9 27 = log 27/log 9 both to base 10 = log (3)^3 / log (3)^2 = 3 log 3 / (2 log3) = 3/2 and the solve. all the best
