richiesmasher
Junior Member
- Joined
- Dec 15, 2017
- Messages
- 111
Here is an equation, with three varibles x, z, and L
. . .(2xy)/z + 2x - L = 0
I want to make x the subject.
I would think to do this:
. . .(2xy)/z + 2x - L = 0
Bring L across
. . .(2xy)/z + 2x = L
Then factorize the left side:
. . .2x(y/z + 1) = L
Simplify the term (y/z + 1) into ((y + z)/z):
. . .2x ((y + z)/z) = L
Then multiply both sides by z:
. . .2x(y + z) = Lz
Divide by (y + z):
. . .2x = Lz/(y + z)
Divide by 2:
. . .x = Lz/(2y + 2z)
Is this correct?
. . .(2xy)/z + 2x - L = 0
I want to make x the subject.
I would think to do this:
. . .(2xy)/z + 2x - L = 0
Bring L across
. . .(2xy)/z + 2x = L
Then factorize the left side:
. . .2x(y/z + 1) = L
Simplify the term (y/z + 1) into ((y + z)/z):
. . .2x ((y + z)/z) = L
Then multiply both sides by z:
. . .2x(y + z) = Lz
Divide by (y + z):
. . .2x = Lz/(y + z)
Divide by 2:
. . .x = Lz/(2y + 2z)
Is this correct?
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