Manipulation: How does [3p (sqrtl{2}/2) (cos(x) + sin(x))] / sin(x) become [3p (cos(x) + sin(x))] / [sqrt{2} sin(x)] ?

[urimagic]

Hi friends,

most probably the most stupidest question anyone here could ever get, but here goes:

 

[BigBeachBanana]

[math]\dfrac{\sqrt{2}}{2} \cdot \dfrac{\sqrt{2}}{\sqrt{2}}= \dfrac{2}{2\sqrt{2}}= \dfrac{1}{\sqrt{2}}[/math]

 

[urimagic]

[math]\dfrac{\sqrt{2}}{2} \cdot \dfrac{\sqrt{2}}{\sqrt{2}}= \dfrac{2}{2\sqrt{2}}= \dfrac{1}{\sqrt{2}}[/math]

Thank you...very kind..stay blessed..