Match the post#

Denis

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Feb 17, 2004
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Using digits 0 to 9 in ascending order and in descending order,
and using "all the tricks of the trade", create equations showing
as result 1000 + post#.

As example, this post# is 1, so the 2 equations must equal 1001.

0 + 1 + 2*(3 + 4*5 + 6*78 + 9) = 1001
987 + 6 - 5 + 4 - 3 + 2 + 10 = 1001

Btw, 0! = 1 is allowed.

I'll do the next one (further example)...then whoever is interested
can do 1003...and so on...

RULE: ALL posts require this to be done ...... OK DAN?!
 
Last edited:

Denis

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0*1 + 2 * 3*(4 + 5! + 6*7 - 8 + 9) = 1002
√9 * (8 - 7 + 6*54 + 3^2 + 1 - 0!) = 1002

So whoever is next (if any!) gets to do 1003.
 
Last edited:

topsquark

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Oh not here, too! 🦖 (stompstompstompstompstomp...)

-Dan

Moderator Edit: Denis lends Dan a hand:

0!/.1 + 234 - 5*6 + 789 = 1003

9*87 + 6 + 5 - 4 + 3 + 210 = 1003
 
Last edited by a moderator:

ksdhart2

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Alright, so here's my results for 1004:

  • \(\displaystyle 123 + 4(5 \cdot 6 \cdot 7 + 8) + 9 = 1004\)
  • \(\displaystyle 9 + 8(76 + 5 + 43) + 2 + 1 = 1004\)
 

Denis

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KS, you forgot the 0's; go stand in the corner!

0 + 1*2 - 3 + 4^5 + 6 - 7 - 8 - 9 = 1005

9 - 8 - 7 - 6 + 5 - 4*3 + 2^10 = 1005
 

ksdhart2

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Okay, I'll go sit in the corner for 0 minutes.
  • \(\displaystyle 0 + 1 + 23 \cdot 4 \cdot 5 + 67 \cdot 8 + 9 = 1006\)
  • \(\displaystyle 9 \cdot 87 + 6 + 5 \cdot 43 + 2 \cdot 1 + 0 = 1006\)
 

Denis

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0*123 + 4^5 + (6 - 7)*(8 + 9) = 1007

9 - 8 - 7 - 6 - 5*(4 - 3) + 2^10 = 1007
 

Denis

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0*1 + 2*3 + 4^5 + 67 - 89 = 1008

987*(6 - 5)*(4 - 3) + 21.0 = 1008

....Glad to see ya'll enjoying this !!
 

Harry_the_cat

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0 + 1 + 2*3 + 4^5 + 67 - 89 = 1009

987 * (6-5) + (4-3) * 21 + 0! = 1009
 

ksdhart2

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\(\displaystyle 0! + 1 + 2 \cdot 3 + 4^5 + 67 - 89 = 1010\)

\(\displaystyle 9 + 87 + 6 + 5 + 43 \cdot 21 = 1010\)
 

Denis

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0*123 + 4^5 - 6 - 7*(-8 + 9) = 1011

9 - 87 + 65*(4 - 3) + 2^10 = 1011
 

Harry_the_cat

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0 x 123 + 4^5 - 6 - 7 - 8 + 9 = 1012
-98/7 + 6 - 5 + 4 - 3 + 2^10 = 1012
 
Last edited:

Harry_the_cat

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0 x 1 - 2 + 3 + 4^5 - 6 - 7 - 8 + 9 = 1013
(98 - 76) x 5 + 43 x 21 + 0 = 1013
 

Denis

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0 + 1 - 2 + 3 + 4^5 - 6 - 7 - 8 + 9 = 1014
(98 - 76) x 5 + 43 x 21 + 0! = 1014

AHEM!
 

Denis

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01 - 2 - .3 + 4^5 - 6 - .7 + 8 - 9 = 1015

9 - 8 - 7 - .6 - 5 - .4 + 3 + 2^10 = 1015
 

lookagain

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0 - 1 + 23*45 + 6 - 7 - 8 - 9 = 1016

(9 + 8 - 7 - 6)^5 - 4 - 3 - 2 + 1 + 0 = 1016
 

ksdhart2

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\(\displaystyle 0 + 1^2 + 3 + 4 \cdot 56 + 789 = 1017\)

\(\displaystyle 9 + 8 + 7 + 6 × 54 \cdot 3 + 21 + 0 = 1017\)
 

Denis

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You forgot a "0" again KS!!

-0! + 1234 - 5*6*7 - 8 + √9 = 1018

987 + 6*5 + 4 - 3 + 21*0 = 1018
 

ksdhart2

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At least it's only one zero this time. Progress, I suppose 🥶

\(\displaystyle 0 + 1 + 2 + 3 + 4 \cdot 56 + 789 = 1019\)

\(\displaystyle 987 + 6 + 5 \cdot 4 + 3 + 2 + 1 + 0 = 1019\)
 

lookagain

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0 + 1 + 23*45 - 6 + 7 - 8 - 9 = 1020

(9 + 8 - 7 - 6)^5 - 4 - (3 + 2 + 1)*0 = 1020
 
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