What you wrote is this:Can you help me to solve this
\sum (from j=1 to n) (tg(x/2))/2 = ctg (x/2^n)/2^n -ctg x
Thanks in advance
This is setup, I'm not sure if this is mistake. I was thinking maybe there is mistake, but this is setup in my book. It's maybe tg (x/2)/2^jWhat you wrote is this:
[math]\sum_{j = 1}^n \dfrac{tg \left ( \dfrac{x}{2} \right )}{2} = \dfrac{ctg \left ( \dfrac{x}{2^n} \right )}{2^n} - ctg(x)[/math]
There is no "j" in the summand. Please fix the problem statement.
-Dan
As posted the problem does not make sense. Please post a picture of your assignment/problem as it was given you.This is setup, I'm not sure if this is mistake. I was thinking maybe there is mistake, but this is setup in my book. It's maybe tg (x/2)/2^j
I know, I tried to solve it that way, but couldn'tIf you set is correct, then the left hand side equals n((tg(x/2))/2)
\(\displaystyle \sum_{i=1}^n a = a + a + a + ... + a = na\).
Your a is simply (tg(x/2))/2
Seeing as the original statement is incorrect for any value of n this does not surprise me. You will have to find a corrected version of the problem before you can do it.I know, I tried to solve it that way, but couldn't