(sqrt2x-5y)^2
D Deleted member 4993 Guest Aug 23, 2010 #2 rame said: (sqrt2x-5y)^2 Click to expand... What do you need to do? - there is no "question. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
rame said: (sqrt2x-5y)^2 Click to expand... What do you need to do? - there is no "question. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Aug 23, 2010 #3 Another thing:\displaystyle Another \ thing:Another thing: Is that: (2x−5y)2 or (2x−5y)2?\displaystyle Is \ that: \ (\sqrt2 x-5y)^2 \ or \ (\sqrt{2x}-5y)^2?Is that: (2x−5y)2 or (2x−5y)2? If you don′t start using grouping symbols, unless you marry the boss′ daughter, you′re doom.\displaystyle If \ you \ don't \ start \ using \ grouping \ symbols, \ unless \ you \ marry \ the \ boss' \ daughter, \ you're \ doom.If you don′t start using grouping symbols, unless you marry the boss′ daughter, you′re doom.
Another thing:\displaystyle Another \ thing:Another thing: Is that: (2x−5y)2 or (2x−5y)2?\displaystyle Is \ that: \ (\sqrt2 x-5y)^2 \ or \ (\sqrt{2x}-5y)^2?Is that: (2x−5y)2 or (2x−5y)2? If you don′t start using grouping symbols, unless you marry the boss′ daughter, you′re doom.\displaystyle If \ you \ don't \ start \ using \ grouping \ symbols, \ unless \ you \ marry \ the \ boss' \ daughter, \ you're \ doom.If you don′t start using grouping symbols, unless you marry the boss′ daughter, you′re doom.
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Aug 23, 2010 #4 BigGlenntheHeavy said: Is that: (2x−5y)2 or (2x−5y)2?\displaystyle Is \ that: \ (\sqrt2 x-5y)^2 \ or \ (\sqrt{2x}-5y)^2?Is that: (2x−5y)2 or (2x−5y)2? Click to expand... Huh?
BigGlenntheHeavy said: Is that: (2x−5y)2 or (2x−5y)2?\displaystyle Is \ that: \ (\sqrt2 x-5y)^2 \ or \ (\sqrt{2x}-5y)^2?Is that: (2x−5y)2 or (2x−5y)2? Click to expand... Huh?
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Aug 24, 2010 #5 Another possibility: (2x−5y)2\displaystyle \text{Another possibility:} \ (\sqrt{2x - 5y})^2Another possibility: (2x−5y)2
Another possibility: (2x−5y)2\displaystyle \text{Another possibility:} \ (\sqrt{2x - 5y})^2Another possibility: (2x−5y)2
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Aug 24, 2010 #6 I love it!\displaystyle \text{I love it!}I love it! \(\displaystyle \text{We have: }\;(\text{sqrt}2x\!\!-\!\!5y)}^2\) . . . \(\displaystyle \text{which could equal: }\;\begin{Bmatrix} \left(\sqrt{2}\!\cdot\!x - 5y\right)^2 \\ \\[-3mm] \left(\sqrt{2x} - 5y\right)^2 \\ \\[-3mm] \left(\sqrt{2x-5}\cdot y\right)^2 \\ \\[-3mm] \left(\sqrt{2x-5y}\,\right)^2 \end{array}\) . . and no instructions . . .\displaystyle \text{and no instructions . . .}and no instructions . . . If I had a nickel . . . .
I love it!\displaystyle \text{I love it!}I love it! \(\displaystyle \text{We have: }\;(\text{sqrt}2x\!\!-\!\!5y)}^2\) . . . \(\displaystyle \text{which could equal: }\;\begin{Bmatrix} \left(\sqrt{2}\!\cdot\!x - 5y\right)^2 \\ \\[-3mm] \left(\sqrt{2x} - 5y\right)^2 \\ \\[-3mm] \left(\sqrt{2x-5}\cdot y\right)^2 \\ \\[-3mm] \left(\sqrt{2x-5y}\,\right)^2 \end{array}\) . . and no instructions . . .\displaystyle \text{and no instructions . . .}and no instructions . . . If I had a nickel . . . .
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Aug 24, 2010 #7 For readers who need information about properly typing mathematical expressions using a keyboard, KARL'S NOTES is a good read.
For readers who need information about properly typing mathematical expressions using a keyboard, KARL'S NOTES is a good read.