summer_storms
New member
- Joined
- May 16, 2007
- Messages
- 8
The total profit (in dollars) for sales of "x" rowing machines is given by
P(x) = 0.2x^2 + 300x - 200
What is the profit if 500 are sold? For what value of "x" will the profit be at a maximum?
What I have done so far:
P(x) = 0.2x^2 + 300x - 200
Let x = 500
P(500) = 0.2(500)^2 + 300(500) - 200
P(500) = 10,000 + 150,000 - 200
P(500) = 160,000 - 200
P(500) = 159,800
P(500)/500 = 159,800/500
P = 319.60
The profit is $319.60
How would I go about figuring the second part? When the value of x profit will be at a maximum?
Thank you for your time.
P(x) = 0.2x^2 + 300x - 200
What is the profit if 500 are sold? For what value of "x" will the profit be at a maximum?
What I have done so far:
P(x) = 0.2x^2 + 300x - 200
Let x = 500
P(500) = 0.2(500)^2 + 300(500) - 200
P(500) = 10,000 + 150,000 - 200
P(500) = 160,000 - 200
P(500) = 159,800
P(500)/500 = 159,800/500
P = 319.60
The profit is $319.60
How would I go about figuring the second part? When the value of x profit will be at a maximum?
Thank you for your time.