Find the absolute maximum and absolute minimum values of f on the given interval.
f(x)= x-2cosx [-pi, pi]
So i differentiated:
f'(x)= 1+2sinx
I think this is right.
Then I ended with sinx=-1/2.
This is where I get stuck. I think the next step goes back to trig, but I can't remember. I don't know how to get the values from what I have ended up with.
f(x)= x-2cosx [-pi, pi]
So i differentiated:
f'(x)= 1+2sinx
I think this is right.
Then I ended with sinx=-1/2.
This is where I get stuck. I think the next step goes back to trig, but I can't remember. I don't know how to get the values from what I have ended up with.