NormsBreaker
New member
- Joined
- Oct 3, 2020
- Messages
- 2
Suppose I have a function of the form[MATH] f(x) = g(y) [/MATH]? Then how am I supposed to find the mean values of x or y ?
I have the knowledge to find mean values of functions of the form[MATH]y=f(x)[/MATH]using the area under the curve but not more than that.
Although I am more interested in a generalized solution, currently I am stuck with a function of the form
[MATH] y=\frac{kx^3}{e^{mx} -1} [/MATH]
Where k and m are constants.
And I am interested in the mean value of x i. e.[MATH] <x>. x \in (0, \infty) y \in (0, 1.248 \times 10^{-26}] [/MATH]So far, I've tried to somehow represent the above function in the form of[MATH]x=f(y)[/MATH], but to no success. Even after using the McLaurin series expansion, I couldn't do it. It always translates to the form :
[MATH] f(x) = g(y) ? [/MATH]
I have the knowledge to find mean values of functions of the form[MATH]y=f(x)[/MATH]using the area under the curve but not more than that.
Although I am more interested in a generalized solution, currently I am stuck with a function of the form
[MATH] y=\frac{kx^3}{e^{mx} -1} [/MATH]
Where k and m are constants.
And I am interested in the mean value of x i. e.[MATH] <x>. x \in (0, \infty) y \in (0, 1.248 \times 10^{-26}] [/MATH]So far, I've tried to somehow represent the above function in the form of[MATH]x=f(y)[/MATH], but to no success. Even after using the McLaurin series expansion, I couldn't do it. It always translates to the form :
[MATH] f(x) = g(y) ? [/MATH]