Y yvonne weinert New member Joined Sep 17, 2006 Messages 3 Sep 17, 2006 #1 The supplement of an angle is 9 times greater then the measure of the complement of the angle. Find the measure of the angle.
The supplement of an angle is 9 times greater then the measure of the complement of the angle. Find the measure of the angle.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Sep 17, 2006 #2 Solve for x: \(\displaystyle \pi - x = 9\left( {\frac{\pi }{2} - x} \right)\)
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Sep 17, 2006 #3 let a = the angle 180 - a = supplement of the angle 90 - a = complement of the angle now, translate the sentence into an equation ... The supplement of an angle is 9 times greater then the measure of the complement of the angle. 180 - a = 9(90 - a) solve for "a" ...
let a = the angle 180 - a = supplement of the angle 90 - a = complement of the angle now, translate the sentence into an equation ... The supplement of an angle is 9 times greater then the measure of the complement of the angle. 180 - a = 9(90 - a) solve for "a" ...
Y yvonne weinert New member Joined Sep 17, 2006 Messages 3 Sep 19, 2006 #5 Actually 180-x=9(90-x) is correct