Mixture problem: A farmer has 242 goats and sheep in total.

falcios

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How do I go about solving this mixture problem?

A farmer has 242 goats and sheep in total. He sells half of the goats and buys 28 more sheep. In the end he has three times as many sheep as goats. How many sheep did he have to start with?


Thanks in advance.
 
A farmer has 242 goats and sheep in total. He sells half of the goats and buys 28 more sheep. In the end he has three times as many sheep as goats. How many sheep did he have to start with?
g = number of goats
242 - g = number of sheep

half the goats = g/2
28 more sheep = 28 + 242 - g

Please show your work.

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