**Re: HOW MANY GEESE??**
lori said:

A flock of geese on a pond were being observed contiuously.

At 1:00 pm 1/5 of the geese flew away.

At 2:00 pm 1/8 of the geese flew away.

At 3:00 pm 3 times as many geese as has flown away at 1:00 pm flew away, leaving 28 geese on the pond. At no other time did any geese arrive or fly away or die. How many geese were in the original flock?

I am at atotal loss on this question. If someone could help me get started I would greatly appreciate it!

Let T be the number of Geese. T will be the total number that flew away plus 28, right?

At 1PM, (1/5)T flew away.

At 2PM, there are only (4/5)T left on the pond, and it is stated that (1/8) of them flew away. So (1/8) of (4/5)T is (1/8)(4/5)T = (1/10)T.

At 3 PM, 3 times the number of geese that flew away at 1PM flew away. This is 3(1/5)T = (3/5)T.

Therefore the total, T, of geese is:

T = (1/5)T + (1/10T) + (3/5)T + 28

Now try to get T by itself.