[MOVED] Solve sin(theta) = -sqrt(3)/2 on 0deg <= theta &l

[NEHA]

Solve the following equation if 0degrees <= theta <360degrees :

sin(theta) = - sqrt(3) / 2

:? :?:

 

[stapel]

Look at the table they gave you of basic reference angles.

Eliz.

 

[NEHA]

theta = sin^(-1)(-sqrt(3)/2)

sin(60degrees) = sqrt(3)/2

sin(- 60degrees) = -sqrt(3)/2

values of theta: 240degrees and 300degrees

thumbs up or down?

 

[stapel]

Since sine is negative in the third and fourth quadrants, then, by nature of the sine wave, given that sin(60°) = sqrt[3]/2, then sin(180° + 60°) = -sqrt[3]/2 and sin(360° - 60°) = -sqrt[3]/2.

So theta ("\(\displaystyle \theta\)") is 240° or 300°.

Eliz.