What if x= 0? You can't divide by 0!No adding or subtracting on this one.
\(\displaystyle 5x = 10x^{2}\)
\(\displaystyle 5 = \dfrac{10x^{2}}{x}\)
Yes, IF you can answer my question!\(\displaystyle 5 = 10x\)
\(\displaystyle x = \dfrac{1}{2}\) Right strategy?
What if x= 0? You can't divide by 0!
Yes, IF you can answer my question!
Or you could write it as \(\displaystyle 10x^2- 5x= 5x(2x- 1)= 0\).
That's a quadratic equation. Do you see that there are two values of x that satisfy it?
How algebraically did you get from \(\displaystyle 5x = 10x^{2}\) to \(\displaystyle 10x^{2} - 5x = 0\) ???