hi
I think I misunderstood a part of a book
we can't multiply or divide both sides of an equation by 0 right?
in one part of that book.
we have this rational equation
[MATH]\frac{2x}{(x-3)} + \frac{5}{(x+3)} = \frac{36}{(x^2-9)}[/MATH]for solving it we multiply both side by lcd that is[MATH](x-3)(x+3)[/MATH]and solve the equation [MATH]2x(x+3) + 5(x-3) = 36[/MATH] the answers will be [MATH]x=\frac{-17}{2}[/MATH] and [MATH]x = 3[/MATH]so if [MATH]x = 3[/MATH] that means [MATH](x-3) = 0 [/MATH] and we are multiplying both sides by 0
can we do that ? or I'm missing something or totally misunderstood the subject
thank you.
I think I misunderstood a part of a book
we can't multiply or divide both sides of an equation by 0 right?
in one part of that book.
we have this rational equation
[MATH]\frac{2x}{(x-3)} + \frac{5}{(x+3)} = \frac{36}{(x^2-9)}[/MATH]for solving it we multiply both side by lcd that is[MATH](x-3)(x+3)[/MATH]and solve the equation [MATH]2x(x+3) + 5(x-3) = 36[/MATH] the answers will be [MATH]x=\frac{-17}{2}[/MATH] and [MATH]x = 3[/MATH]so if [MATH]x = 3[/MATH] that means [MATH](x-3) = 0 [/MATH] and we are multiplying both sides by 0
can we do that ? or I'm missing something or totally misunderstood the subject
thank you.