G

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w^2 - 4w w-4

___________ . ___________

w^2-8w + 16 w^2 + w

w(w-4) . w-4 1

______ ________ = _________

? w(w+1)

This is all I have broke down so far :?

G

w^2 - 4w w-4

___________ . ___________

w^2-8w + 16 w^2 + w

w(w-4) . w-4 1

______ ________ = _________

? w(w+1)

This is all I have broke down so far :?

You was agettin' there, mom!afreemanny said:

w^2 - 4w w-4

___________ . ___________

w^2-8w + 16 w^2 + w

w(w-4) . w-4 1

______ ________ = _________

? w(w+1)

This is all I have broke down so far :?

w^2 - 8w + 16 = (w - 4)(w-4)

SO:

w(w - 4)(w - 4)

==============

(w - 4)(w - 4)w(w + 1)

look at all them (w-4)'s; cancel 'em out:

w

======

w(w + 1)

now shoot the 2 w's:

1

====

w + 1

Denis is absolutely correct . . . here's my version.

You factored everything nicely . . . except the trinomial.

. . Are you fuzzy on that procedure?

. . . . . . . . . . . . . . . . . .w(w - 4) . . . .w - 4. . . w<sup>2</sup> - 4w . . . . w - 4

. --------------- . -----------

. w<sup>2</sup>- 8w + 16 . . w<sup>2</sup> + w

.

Factor

. . . . . . . . . . . . . . . (w - 4)(w - 4) . w(w + 1)

Then cancel factors common to the numerator and the denominator.

[I'm sure you're familiar with this part, though]

. . There is a "single w" on top and another on the bottom.

. . There is a (w - 4) on top and another on the bottom.

. . And there is <u>another</u> pair of (w - 4)'s to cancel.

. . . . . . . . . . 1

Answer: . --------

. . . . . . . . w + 1

G

Thanks so much ! I get stuck on the dardest things!