eddy2017
Elite Member
- Joined
- Oct 27, 2017
- Messages
- 2,525
Hi, there dear friends:
A bag contains four marbles. One marble is blue, one is red, one is white, and one is yellow. Two marbles are draw from the bag by removing one marble and then, without replacing the first marble, removing a second marble. In how many ways can the two marbles be drawn from the bag so that at least one of the marbles is red?
There are two marbles drawn. The problem is asking about combinations ("how many ways"), not about probability.
Solution
With one blue, one red, one white, one yellow marbles in the bag -- and without replacement (which is important) --
The possible results are:
B R
B W
B Y
R B (note: this "way" is different from B R)
R W
R Y
W B
W R
W Y
Y B
Y R
Y W
I do all possible combinations.
There are 6 possible combinations.
In how many ways do I have the possibility of drawing a red marble?. Well, in 6 different ways.
Is this good or am I missing something here?
Thanks a lot for your help and time.
A bag contains four marbles. One marble is blue, one is red, one is white, and one is yellow. Two marbles are draw from the bag by removing one marble and then, without replacing the first marble, removing a second marble. In how many ways can the two marbles be drawn from the bag so that at least one of the marbles is red?
There are two marbles drawn. The problem is asking about combinations ("how many ways"), not about probability.
Solution
With one blue, one red, one white, one yellow marbles in the bag -- and without replacement (which is important) --
The possible results are:
B R
B W
B Y
R B (note: this "way" is different from B R)
R W
R Y
W B
W R
W Y
Y B
Y R
Y W
I do all possible combinations.
There are 6 possible combinations.
In how many ways do I have the possibility of drawing a red marble?. Well, in 6 different ways.
Is this good or am I missing something here?
Thanks a lot for your help and time.