E etherealchaos New member Joined Feb 13, 2006 Messages 4 Feb 13, 2006 #1 Here's my problem. Really stuck on it! Assume a, b, and c are positive and solve for x. |x/a + 1/b| < c
Here's my problem. Really stuck on it! Assume a, b, and c are positive and solve for x. |x/a + 1/b| < c
D Denis Senior Member Joined Feb 17, 2004 Messages 1,706 Feb 13, 2006 #2 I will gladly help you Thursday if you show your efforts Today :idea: %$#@^&$%@ ========== (Denis, for TK)
I will gladly help you Thursday if you show your efforts Today :idea: %$#@^&$%@ ========== (Denis, for TK)
pka Elite Member Joined Jan 29, 2005 Messages 11,990 Feb 13, 2006 #3 Because a, b, and c are positive, |x/a + 1/b| < c is equivlant to |bx+a|<abc.