Need help finding domain of f(x) = x/square root(x-2)

nicolek

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Mar 3, 2007
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f(x) = x/square root(x-2)

What I have come up with is probably wrong:
square root(x-2) cannot equal 0
square root (x-2) cannot equal -2
square root (x-2 cannot equal 2
x cannot equal 4

I don't know where to go from here?
 
Look closer at the denominator, \(\displaystyle \sqrt{x-2}\).

What values of x result in a negative inside the radical or 0?.
 
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